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a line has this equation:y=1/4x-1. what’s a perpendicular line that goes through (3,-8)

Sagot :

Devishri1977idn

Answer:

y = -4x + 4

Step-by-step explanation:

y = (1/4)x - 1

m = (1/4)

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/4)

                                                                      [tex]= (-1)*\frac{4}{1}\\\\=-4[/tex]

(3 , -8)

y - y1 =m(x -x1)

y -[-8] = -4(x - 3)

y + 8 = -4x + 12

    y = -4x + 12 - 8

    y = -4x + 4

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