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How is it possible that the sum of two quadratic trinomials is a linear​ binomial?



The coefficients of the terms whose exponents are



nothing sum to



▼



​Thus, the result is a linear binomial of degree



nothing.

Sagot :

Answer:

Follows are the responses to this question:

Step-by-step explanation:

In this question, if both quadratic trinomials include opposite [tex]x^2[/tex] terms of signs, it's indeed possible that's also possible, which is why the quadratic [tex]x^2+2x +1 \ and \ -x^2 + 4x -5[/tex] cancels the  [tex]x^2 \ to\ 6x- 4[/tex], which would be a linear binomial.  that's why this statement is true that the "two quadratic trinomials have [tex]x^2[/tex] -terms in signs opposite".

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