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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If BC=6 and DC=4, what is the length of AC ?

Sagot :

Rtwenefouridn

Step-by-step explanation:

BC^2 + DC^2 = AC^2

6^2 + 4^2 =AC^2

36 + 16 = AC^2

52=AC^2

√52=AC

AC=7.2111

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