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Given the figure below, find EF if CA = (6n) and EF = (n + 8)

Given The Figure Below Find EF If CA 6n And EF N 8 class=

Sagot :

MrRoyalidn

Answer:

[tex]EF = 12[/tex]

Step-by-step explanation:

Given

[tex]CA =6n[/tex]

[tex]EF= n + 8[/tex]

Required

Find CN

From the attachment:

[tex]EF = CD\ and\ CD = DA[/tex]

Where

[tex]CA = CD + DA[/tex]

This means that:

[tex]CA = CD + CD[/tex]

[tex]CA = 2CD[/tex]

or

[tex]CA = 2*EF[/tex]

This gives:

[tex]6n = 2*(n+8)[/tex]

Open bracket

[tex]6n = 2n+16[/tex]

Collect anf simplify like terms

[tex]4n = 16[/tex]

[tex]n= 4[/tex]

So:

[tex]EF= n + 8[/tex]

[tex]EF = 4 + 8[/tex]

[tex]EF = 12[/tex]

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