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Find the vertex and focus of the
parabola.
x2 + 6x – 8y + 1 = 0

Sagot :

Answer:

Step-by-step explanation:

Vertex: -3, -1

Focus: -3, 1

Varshamittal029idn

Vertex of the parabola is (-3,-1)

Focus is (-3,1)

What is the vertex form of parabola?

  • The standard form of the parabola is given by y = ax2 + bx + c
  • The vertex form of the parabola is y-k = a(x - h)^2
  • vertex of the parabola is (h,k)
  • Focus of the parabola is (h,k+p)

Given parabola equation is x^2+6x-8y+1=0

x^2+6x = 8y-1

x^2+6x+9 = 8y-1+9

(x+3)^2 = 8y+8

(x+3)^2 = 8(y+1)

(y+1) = 1/8 (x+3)^2

Here vertex V(h,k) = (-3,-1)

Focus = (-3,1)

Hence, Vertex of the parabola is (-3,-1)

Focus of the parabola is(-3,1)

Learn more about parabola here:

https://brainly.com/question/4291574

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