Novancarrollidn
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Sue is 15 years older than Mike. in 5 years mikes’s age will be ½ sue’s age. What is the present age of each?

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Sagot :

Alexaxelidn

Answer:

5

Step-by-step explanation:

Sue in 5 years would 20, meaning Mike would be 10. Subtract 5 from Mike to get their current age.

Leora03idn

Answer:

Mike= 10 years old

Sue= 25 years old

Step-by-step explanation:

Let the present age of Sue be s years old, while that of Mike be m years old.

Present

s= m +15 -----(1)

In 5 years

Sue's age= s +5

Mike's age= m +5

Given that Mike would be ½ of Sue's age in 5 years,

m +5= ½(s +5)

Multiply both sides by 2:

2(m +5)= s +5

Expand:

2m +10= s +5

2m +10 -5= s

s= 2m +5 -----(2)

Substitute (1) into (2):

m +15= 2m +5

2m -m= 15 -5

m= 10

Substitute m= 10 into (1):

s= 10 +15

s= 25

Thus, the present age of Mike is 10 years old and the present age of Sue is 25 years old.

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