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Which of the following equations is represented by a line passing through (-9, 7) and (3, 3) in the
standard (x, y) coordinate plane?

Sagot :

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Answer:

y = -1/3x + 4

Step-by-step explanation:

(-9, 7) and (3, 3)

Slope:

m=(y2-y1)/(x2-x1)

m=(3-7)/(3+9)

m=(-4)/12

m= -1/3

Slope-intercept:

y - y1 = m(x - x1)

y - 7 = -1/3(x + 9)

y - 7 = -1/3x - 3

y = -1/3x + 4

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Step-by-step explanation:

[tex]soln \\ \frac{3 - 7 }{3 - - 9} \\ = \frac{ - 4}{ - 12} \\ = \frac{1}{3 } \\ \frac{y - 7}{x - 3} = \frac{1}{3} \\ then \: you \: cross \: multiplication. \\ 3(y - 7) = 1(x - 3) \\ 3y - 7 = x - 3 \\ 3y = x - 3 + 7 \\ 3y = x + 4 \\ \frac{3y}{3} = \frac{x}{3} + \frac{4}{3} \\ y = \frac{x}{3} + \frac{4}{3} [/tex]

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