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Answer:
C. 30 kJ
Explanation:
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In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:
[tex]\Delta G= \Delta H-T\Delta S[/tex]
It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:
[tex]\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol[/tex]
Therefore, the answer is C. 30 kJ .
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