Desmondboateng335idn
Answered

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[tex] {x }^{2} = {16}^{x?} [/tex]
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Sagot :

x is -1/2 . Using the Lambert W function.
x^2=16^x => x^2=(2^4)^x
x^2=2^4x => x=2^2x
x=(e^in(2))^2x => x=e^2in(2)x
e^2in(2)x1/x=1
xe^-2in(2)x=1 /*1
-xe^-2in(2)x=-1
-2in(2)xe^-2in(2)x=-2in(2)
W(-2in(2)xe^-2in2x)=W(-2in(2))
-2in(2)x=W(-2in(2))
X=-W(-2in(2))/2in(2)
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