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Answer:
[tex](a)\ Pr = 0.25[/tex]
[tex](b)\ Pr = 0.50[/tex]
Step-by-step explanation:
Given
[tex]Flips = 4[/tex]
First, we calculate the sample size;
The coin has two possible outcomes (i.e. head or tail) and the number of flips is 4.
So, the sample size (N) is:
[tex]N = 2^4[/tex]
[tex]N = 16[/tex]
Solving (a): Probability the outcome of the first and last flip is head.
The possible outcomes for this event are:
[tex]n = \{(HHHH), (HHTH), (HTHH),(HTTH)\}[/tex]
[tex]n(n) = 4[/tex]
The probability is:
[tex]Pr = \frac{n(n)}{N}[/tex]
[tex]Pr = \frac{4}{16}[/tex]
[tex]Pr = 0.25[/tex]
Solving (a): Probability that the outcome of at least 2 consecutive flips is head.
The possible outcomes for this event are:
[tex]n = \{(HHHH), (HHHT),(HHTH), (HTHH),(THHH),(TTHH),(HHTT), (THHT)\}[/tex]
[tex]n(n) = 8[/tex]
The probability is:
[tex]Pr = \frac{n(n)}{N}[/tex]
[tex]Pr = \frac{8}{16}[/tex]
[tex]Pr = 0.50[/tex]