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Sagot :
Answer:
[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]
[tex] \huge\red{ \mid{ \underline{ \overline{ \tt Fe }} \mid}}[/tex]
→ Molar Mas = 55.85 g/mol
[tex] \huge\orange{ \mid{ \underline{ \overline{ \tt NaCl }} \mid}}[/tex]
→ Molar Mass = 58.44 g/mol
[tex] \huge\red{ \mid{ \underline{ \overline{ \tt CH₄ }} \mid}}[/tex]
→ Molar Mass = 16.02 g/mol
[tex] \huge\orange{ \mid{ \underline{ \overline{ \tt Ca(OH)₂ }} \mid}}[/tex]
→ Molar Mass = 74.10 g/mol
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]
Answer:
Fe -> 55.85g/mol
NaCl-> 58.44g/mol
CH₄->16.02g/mol
Ca(OH)₂->74.10g/mol
Explanation:
NaCl = 22.990 + 35.45 = 58.44g/mol
CH₄ = 12.011 + (1.008 × 4) = 16.043 g/mol
Ca(OH)₂ = 40.078 + 2(15.999 + 1.008) = 74.092 g/mol
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