Answer:
The equation of the circle is
[tex](x - h) {}^{2} + (y - k) = {r}^{2} [/tex]
where (h,k) is the center and r is the radius.
The center is (-1,1) so plug that in the equation.
[tex](x - ( - 1)) {}^{2} + (y - 1) {}^{2} = {r}^{2} [/tex]
[tex](x + 1) {}^{2} + (y - 1) {}^{2} = {r}^{2} [/tex]
The radius of the circle is 3 so plug that in for r.
[tex](x + 1) {}^{2} + (y - 1) {}^{2} = {3}^{2} [/tex]
[tex](x + 1) {}^{2} + (y - 1) {}^{2} = 9[/tex]
