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How do you write an equation of a line that passes through (4,3) and has a slope of 2?

Sagot :

Answer:

y = 2x - 5

Step-by-step explanation:

y-intercept form is y = mx + b, where m is the slope and b is the y-intercept. We know the slope is 2, so all that's left is to find the y-intercept. To do this, for every 1 we subtract from x in (4,3), we take away 2 from y because the slope is two. We keep doing this until x is zero. The remaining y-value is the y-intercept.  

Answer:

[tex]y = 2x-5[/tex], see below.

Step-by-step explanation:

There is enough information to make a point slope equation that we can later convert into slope intercept.

Point slope form is:

[tex]y-y_1=m(x-x_1)[/tex]

[tex](x_1,y_1): \text{A point.} \\\\m - \text{Slope.}[/tex]

We are given the slope of 2 and the point (4,3).

Replace the variables with the given information.

[tex]y-y_1=m(x-x_1)\rightarrow y-3=2(x-4)[/tex]

With the equation we will now convert it into slope intercept form:

[tex]y-3=2(x-4)\\\\y-3=2x-8\\\\y-3+3=2x-8+3\\\\\boxed{y=2x-5}[/tex]

Hope this helps!

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