IDNLearn.com offers a comprehensive solution for finding accurate answers quickly. Discover in-depth answers to your questions from our community of experienced professionals.

How do you write an equation of a line that passes through (4,3) and has a slope of 2?

Sagot :

Answer:

y = 2x - 5

Step-by-step explanation:

y-intercept form is y = mx + b, where m is the slope and b is the y-intercept. We know the slope is 2, so all that's left is to find the y-intercept. To do this, for every 1 we subtract from x in (4,3), we take away 2 from y because the slope is two. We keep doing this until x is zero. The remaining y-value is the y-intercept.  

Answer:

[tex]y = 2x-5[/tex], see below.

Step-by-step explanation:

There is enough information to make a point slope equation that we can later convert into slope intercept.

Point slope form is:

[tex]y-y_1=m(x-x_1)[/tex]

[tex](x_1,y_1): \text{A point.} \\\\m - \text{Slope.}[/tex]

We are given the slope of 2 and the point (4,3).

Replace the variables with the given information.

[tex]y-y_1=m(x-x_1)\rightarrow y-3=2(x-4)[/tex]

With the equation we will now convert it into slope intercept form:

[tex]y-3=2(x-4)\\\\y-3=2x-8\\\\y-3+3=2x-8+3\\\\\boxed{y=2x-5}[/tex]

Hope this helps!

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.