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Find all the zeros of the function: f(x) = x^2 - 2x - 3


Sagot :

Answer:

x= 3 and -1

Step-by-step explanation:

[tex]f(x) = {x}^{2} - 2x - 3[/tex]

add three to both sides

[tex]3 = {x}^{2} - 2x[/tex]

figure out what half of -2 is

half of -2 is (-1) than square that (-1)^2=1

the 1 is what you add to both sides

[tex]3 + 1 = {x}^{2} - 2x + 1 \\ 4 = {(x - 1)}^{2} [/tex]

than take the square root of both sides

[tex] \sqrt{4} = \sqrt{ {(x - 1)}^{2} } [/tex]

this than equals

+2=x-1

than to find the x values

2=x-1

+1 +1

3=x

-2=x-1

+1 +1

-1=x