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One number is six less than a second number. Twice the first is 4 more than times 6 the second. Find the numbers.

Sagot :

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Answer:

[tex]\text{First number: }-10, \\\text{Second number: }-4[/tex]

Step-by-step explanation:

We can write the following system of equations:

Let the first number be [tex]f[/tex] and the second number be [tex]s[/tex]:

[tex]\begin{cases}f+6=s, \\2f-4=6s\end{cases}[/tex]

Solving, we get:

[tex]\int\limits^a_b {x} \, dx \begin{cases}f+6=s, \\2f-4=6s\end{cases},\\2f-4=6(f+6),\\2f-4=6f+36,\\-40=4f,\\f=\boxed{-10}[/tex]

Solving for [tex]s[/tex]:

[tex]f+6=s,\\-10+6=s,\\s=\boxed{-4}[/tex]

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