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Answer:
B. 87%
Explanation:
First, we calculate the molecular mass of magnesium bromide (MgBr2) as follows;
MgBr2 = 24.3 + 79.9(2)
= 184.1g/mol
Since 1 atom of bromine contains 79.9g, then the mass of two atoms of bromine (Br2) is 79.9 × 2 = 159.8g
Hence, the percentage of bromine (Br2) in MgBr2 is calculated as follows:
% mass of Br2 = mass of Br2/ molecular mass of MgBr2 × 100
% mass of bromine = 159.8/184.1 × 100
% mass of bromine = 0.8680 × 100
% mass of bromine = 86.8%
Approximately, % mass of bromine is 87%