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Sagot :
Answer:
The F-value is approximately 4.57
Step-by-step explanation:
The given parameters are;
The number of oceanfront homes in the sample, n₁ = 21 homes
The standard deviation of the selling prices, s₁ = $45,600
The number homes in the sample of homes one to three blocks from the ocean, n₂ = 18 homes
The standard deviation, s₂ = $21,330
The level of significance, α = 0.01
The F-test is given as follows;
[tex]F = \dfrac{s_1^2}{s_2^2}[/tex]
Therefore, we get;
F = 45,600²/21,330² ≈ 4.57
The F-value ≈ 4.57
The critical value from the F-table = 1.86236.
In this exercise we have to use the knowledge about force to calculate the critical force, in this way we find that:
[tex]F-value: 4.57[/tex]
We know that the information given by the text is:
- The number of oceanfront homes in the sample: [tex]n_1 = 21 homes[/tex]
- The standard deviation of the selling prices: [tex]S_1 = $45,600[/tex]
- The number homes in the sample of homes one to three blocks from the ocean: [tex]n_2 = 18 homes[/tex]
- The standard deviation: [tex]S_2 = $21,330[/tex]
- The level of significance: [tex]\alpha= 0.01[/tex]
The F-test is given as follows:
[tex]F=(S_1^2)/(S^2_2)[/tex]
So we have:
[tex]F=(45.600^2)/(21.330^2)=4.57\\[/tex]
See more about force at brainly.com/question/4456579
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