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A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be described as y = two fifthsx − 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (P, Q)?
y − Q = negative five halves(x − P)
y − Q = two fifths(x − P)
y − P = negative five halvesx − Q)
y − P = two fifths(x − Q)


Sagot :

Answer:

y − Q = negative five halves(x − P)

Retype- y-Q=-5/2(x-P)

Step-by-step explanation:

Due to the lines being perpendicular you would take the 2/5 and flip the number due to it being opposite recpricals (also meaning it would go from positive to negative vice versa)

(Oh yea and also I know its not C because in a different answer someone put C and it was wrong which leaves us with A)

So answer is A)) y-Q=-5/2(x-P)

Edit- This is incorrect because I just got the question wrong on my exam

Answer:

Answer is D) y - P = 2/5(x - Q)

Step-by-step explanation:

I found the answer in the comments, I really hope this helps. I'm sorry, I'm wrong. Good Luck :D

Btw if you read your question compared to this one, it's switched Q,P to P,Q. Those answers are correct, but we thought this was the same question as ours.

A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be described as y = 2/5x − 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (Q, P)?

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