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Find the circumcenter of a triangle ABC with vertices at A(2, 2), B(0, -4), and C(7, -1)
20 POINTS PEOPLE


Sagot :

Answer:

just sum up the 3 sides.

quick side note: I lost my previews writing bc I waited too long too post it :(

but long story short: you get the length of, say, AB by using pythagoras theorem.

[tex] \sqrt{ {2}^{2} + {6}^{2} } [/tex]

do this with BC and CA too

the 2 is just the distance in x-direction and the 6 is just the distance in y-direction

and since a²+b²=c², we need to take the root to get the distance between 2 points

see screenshot for summing up the three distances. the part out of screen is written out above

the sum is 21.011 length units

hope it helps. have a nice day.

feel free to ask questions.

and maybe, if I'm feeling really nice and a lil bored, i leave greeting answers under yours to enable posters to give gives brainliests. if theres no 2and answer at least

View image AlexTrusk
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