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A spinner has 2 blue spaces, 5 yellow spaces, and 1 orange space. If the spinner is spun once, what is the theoretical probability of the spinner NOT stopping on orange? P(Not orange) =

Sagot :

Answer: [tex]\dfrac{7}{8}[/tex]

Step-by-step explanation:

Given

A spinner has 2 blue space, 5 yellow space and 1 orange space i.e. there are total of 8 outcomes possible.

Outcomes other than orange are 2 blue and 5 yellow space

So, the probability of the spinner , Not stopping on orange is

[tex]\Rightarrow P=\dfrac{\text{Non-orange outcomes}}{\text{Total outcomes}}\\\\\Rightarrow P=\dfrac{7}{8}[/tex]

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