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Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]