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Find the value of x in the isosceles triangle shown below​

Find The Value Of X In The Isosceles Triangle Shown Below class=

Sagot :

Answer:

x = [tex]\sqrt{119\\}[/tex]

Step-by-step explanation:

formula for this is [tex]\sqrt{a^{2}-(b/2)^{2}}[/tex] where a is the altitude and b is the base

altitude = 12

base = 10

[tex]\sqrt{12^{2}-(10/2)^{2} }[/tex]

[tex]\sqrt{144-5^{2} }[/tex]

[tex]\sqrt{144-25}[/tex]

[tex]\sqrt{119}[/tex] ≈ 10.9

so I would say x = [tex]\sqrt{119}[/tex] or 10.9, but seeing as thats not an option, then I'm not sure