Answered

IDNLearn.com is your go-to resource for finding precise and accurate answers. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.

What is the empirical formula of a compound containing 5.03 g carbon, 0.42 g hydrogen, and 44.5 g of chlorine

Sagot :

Jbferradoidn

Answer:

CHCl₃

Explanation:

We have the following data:

C = 5.03 g

H = 0.42 g

Cl= 44.5 g

First, we divide each mass by the molar mass (MM) of the chemical element to calculate the moles:

MM(C) = 12 g/mol

moles of C = mass/MM(C) = 5.03 g/(12 g/mol) = 0.42 mol C

MM(H) = 1 g/mol

moles of H = mass/MM(H) = 0.42 g/(1 g/mol) = 0.42 mol H

MM(Cl) = 35.4 g/mol

moles of Cl = mass/MM(Cl) = 44.5 g/(35.4 g/mol) = 1.26 mol Cl

Now, we divide the moles by the smallest number of moles (0.42):

0.42 mol C/0.42 = 1 C

0.42 mol H/0.42 = 1 H

1.26 mol Cl/0.42 = 3 Cl

Thus, the C:H:Cl ratio is 1:1:3.

Therefore, the empirical formula is CHCl₃

Answer:

CHCl₃

Explanation:

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.