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Find the sum of the first 7 terms of the following series, to the nearest integer.
125,50, 20, ...

Sagot :

Answer:

[tex]r = 2.5 \\ sum = \frac{a( {r}^{n - 1} )}{r - 1} \\ = \frac{125( {2.5}^{7 - 1} )}{7 - 1} \\ = \frac{30517.6}{6} \\ = 5086.3[/tex]

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