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In right triangle ABC, sin M = cos 61. If 0

Sagot :

Note: Consider we need to find the value of M if [tex]0^\circ<M<90^\circ[/tex]

Given:

In a right triangle ABC,

[tex]\sin M=\cos 61^\circ[/tex]

To find:

The value of M.

Solution:

We have,

[tex]\sin M=\cos 61^\circ[/tex]

It can be rewritten as:

[tex]\sin M=\cos (90^\circ-29)^\circ[/tex]

[tex]\sin M=\sin 29^\circ[/tex]                   [tex][\because \sin (90^\circ-\theta)=\sin \theta][/tex]

On comparing both sides, we get

[tex]M=29^\circ[/tex]

Therefore, the value of M is 29 degrees.