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A store manager can spend at most $1,000 a day for operating costs and payroll. It costs $100 each day to operate the store and $30 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at MOST.


30x + 100 < 1000


A. X > 30

B. X > 33

C. X < 33

D. X < 30

Sagot :

Abidemiokinidn

Answer:

x < 30

Step-by-step explanation:

Given the inequality expression that denotes the statement as;

30x+100 < 1000

Subtract 100 from both sides

30x + 100 - 100 <1000 - 100

30x < 900

Divide both sides by 30

30x/30 < 900/30

x < 30

Hence the required solution is x < 30

Onyebuchinnajiidn

The number of employee the manager can afford a day is x < 30.

The given parameters:

  • Amount spent a day for operating cost = $1,000
  • The operating cost of the store, = $100 per day
  • Amount paid to the employee = $30 per day

The inequality of the number of employee the manager can afford a day is calculated as follows;

30x + 100 < 1000

collect similar terms together;

30x < 1000 - 100

30x < 900

divide both sides of the equation by 30;

[tex]x <\frac{900}{30} \\\\x <30[/tex]

Thus, the number of employee the manager can afford a day is x < 30.

Learn more about solution to inequality here: https://brainly.com/question/24372553

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