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The expression for the equilibrium constant for the reaction:
Ba3N2 (aq) + 6 H2O(1)-
3 Ba(OH)2 (aq) + 2 NH3 (9)

Sagot :

Unknown767idn

Answer:

[tex]Kc\frac{(Ba3N2)(H2O)^6}{(Ba(OH)2)^3(NH3)^2}[/tex]

Explanation:

Because kc equals products/reactants hope this helps :)

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