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Sagot :
Answer:
The p-value of the test is 0.0013.
Step-by-step explanation:
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
12 is tested at the null hypothesis:
This means that [tex]\mu = 12[/tex]
Standard deviation of 0.5 kilograms.
This means that [tex]\sigma = 0.5[/tex]
Sample of n = 4 specimens. Observed statistic is Xbar (average) = 11.25.
This means that [tex]n = 4, X = 11.25[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{11.25 - 12}{\frac{0.5}{\sqrt{4}}}[/tex]
[tex]z = -3[/tex]
P-value:
Probability of finding a sample mean belo 11.25, which is the p-value of z = -3.
Looking at the z-table, z = -3 has a p-value of 0.0013, thus the this is the p-value of the test.
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