Answer:
9x² + 8
Step-by-step explanation:
The given function to us is ,
[tex]\implies y = 3x {}^{3} + 8x - 7[/tex]
And we need to differentiate the given function with respect to x . Taking the given function and differenciating wrt x , we have
[tex]\implies y = 3x^3 + 8x - 7 [/tex]
Recall that , the derivative of constant is 0 . Therefore ,
[tex]\implies \dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3 + 8x - 7) \\\\\implies\dfrac{dy }{dx}= \dfrac{d}{dx}(3x^3)+\dfrac{d}{dx}(8x) + 0 \\\\\implies\dfrac{dy }{dx}= 3\times 3 . x^{3-1} + 8\times 1 . x^{1-1} \\\\\implies\underline{\underline{\dfrac{dy }{dx}= 9x^2+8}} [/tex]
Hence the derivative of given function is 9x² + 8 .
