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Sagot :
Answer:
Step-by-step explanation:
Given function is,
f(x) = -x² - 2x - 1
= -(x² + 2x + 1)
= -(x + 2)²
Comparing this equation with the vertex form of a quadratic function,
f(x) = a(x - h)² + k
Here, (h, k) is the vertex.
Vertex of the function is (-2, 0)
Leading coefficient of the function = -1
Therefore, parabola will open downwards.
Function will be increasing in the interval (-∞, -2).
Function will be decreasing in the interval (-2, -∞).
Domain of the function → (-∞, ∞)
Range of the function → (-∞, 0]
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