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Sagot :
Answer:
1/9
Step-by-step explanation:
There could be
1. Boy and a boy
2. Boy and a girl
3. Girl and a girl
Only one out of the three could have two girls: the last one. Meaning there is a 1/3 chance of walking into that one and a 1/3 chance that that house would have 2 girls. So it would be a 1/9 chance.
Hope this helps! :)
Answer:
4/9 of the time the other child is a girl.
Step-by-step explanation:
The trick is what's in the third house. There are 3 choices
b g
b b
g g
So writing all three houses together we have
g g g g b g
b g b g b b
g g
The first two houses are identical
1/3 * 1/2 for house 1
1/3 * 1/2 for house 2
1/3 * 1/3 for house 3
Now to explain it about. The probability of choosing 1 of the houses is 1/3 for all of the houses. The second number is the probability of getting 2 girls.
So the total probability is
1/6 + 1/6 + 1/9
2/6 + 1/9 = 6/18 + 2/18 = 8 / 18 = 4/9
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