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S is the midpoint of RT.
If RS = 4x - 3 and RT = 6x - 4,
what’s the value of ST?


Sagot :

Answer:

R__S__T

RT = RS + ST

6x – 4 = ( 4x – 3) + ST

(6x – 4 ) – ( 4x – 3 ) = ST

(6x – 4 ) +( – 4x + 3 ) = ST

2x – 1 = ST

ST = 2x – 1

RS=ST

4x – 3 = 2x – 1

4x – 2x = – 1 +3

2x = 2

x= 2/2

x =1

ST = 2x – 1 = 2(1) – 1 =2 ‐ 1 = 1

ST = 1

I hope I helped you^_^

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