Answered

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The position of a particle s given by x=3-2t+3t^2. What is its instantaneous velocity and instantaneous acceleration as t=3.
At what time is the particle at rest

Sagot :

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Explanation:

velocity = dx/dt

[tex] \frac{dx}{dt} = 6t - 2 = 16[/tex]

acceleration =

[tex] \frac{ {d}^{2}x }{d {t}^{2} } = 6 \ \\ [/tex]

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