Billirisjordyn86idn
Answered

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The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing
for the other three sides, to create a corral. If there is 100 feet of fencing available, what is the maximum possible area of the
corral?

Sagot :

Sqdancefanidn

9514 1404 393

Answer:

  1250 square feet

Step-by-step explanation:

If x is the length of the side perpendicular to the creek, then the third side is (100 -2x) = 2(50 -x). The area is the product of length and width:

  A = x(2)(50-x)

We observe that this is a quadratic function with zeros at x=0 and x=50. The vertex (maximum) of a quadratic function is on the line of symmetry, halfway between the zeros. The value of x there is (0 +50)/2 = 25.

Then the maximum area is ...

  A = (25)(2)(50 -25) = 1250 . . . . square feet

_____

Additional comment

Note that half the length of the fence is used in one direction (parallel to the creek), and half is used in the other direction (perpendicular to the creek). This 50/50 split is the generic solution to all sorts of rectangular corral problems, with or without a creek, with or without internal partitions.

Half the fence is perpendicular to the other half. (If the costs are different in different directions, then the cost is what is split 50/50.)

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