Dgavrilenko6996idn
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The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.
Density Calculation:

Sagot :

Mhanifaidn

Answer:

  • 42390 ft³

Step-by-step explanation:

Since the tanks are congruent, they both have same volume.

If you rejoin them, it will form a cylinder with the radius of 15 ft and height of 120 ft.

The volume of the cylinder:

  • V = πr²h = 3.14*15²*120 = 84780 ft³

The volume of each tank is half the volume of the cylinder:

  • V(tank) = 84780 / 2 = 42390 ft³
  • Radius=r=15ft
  • Height=h=120ft

[tex]\\ \tt\Rrightarrow V=\pi r^2h[/tex]

[tex]\\ \tt\Rrightarrow V=\dfrac{22}{7}(15)^2(120)[/tex]

[tex]\\ \tt\Rrightarrow V=\dfrac{22}{7}(225)(120)[/tex]

[tex]\\ \tt\Rrightarrow V=42390ft^3[/tex]

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