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Answer:
frequency(hz) = ∆E =-0.917×10-¹⁸ J/H
energy(kj/mol) = v=1.384×1015 S-1.
Explanation:
According to Rydberg eqn-
∆E= -Rh ( 1/nf2-1/ni2)
where ∆E- The energy change caused
Rh-Rydberg constant
nf-Principal quantum number of the destination level
ni-Principle quantum number of the initial level
Value of Rh=2.18×10-18J/H
Here nf=4 and ni=7
Therefore ∆E=-2.18×10-18(1/4²-1/7²)
∆E=-0.917×10-¹⁸ J/H
The -ve sign indicates the release of energy from H atom due to relaxation
Frequency v=∆E/h
where h is the planck's constant = 6.626×10-34 J.S
Hence v=0.917×10-18/6.626×10-34
v=1.384×1015 S-1.