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Write an equation for the function graphed below. The y intercept is at (0,0.5)

Write An Equation For The Function Graphed Below The Y Intercept Is At 005 class=

Sagot :

The equation of the graphed function is;

f(x) = -3/[(x + 3)(x - 2)]

  • From the given graph, we see that the vertical assymptotes are at x = -3 and x = 2.

This means that at values of x = -3 or x = 2, the denominator becomes zero and the function becomes undefined.

  • This means that, -3 and 2 are roots of the denominator. Thus, the equation of the denominator is;

(x + 3)(x - 2)

  • Now,we see that the y-intercept is (0, 0.5). This means that when x = 0, y = 0.5.

  • Let the numerator of the equation of the function be named a.

Thus, we have;

f(x) = a/((x + 3)(x - 2))

At (0, 0.5), we have;

0.5 = a/((0 + 3)(0 - 2))

0.5 = a/(-6)

Multiply both sides by -6 to get;

-3 = a

  • Thus, the equation of the function is;

f(x) = -3/((x + 3)(x - 2))

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