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Iron has a density of 7.86g/cm^3. Could a block of metal with a mass of 18.2g and a volume of 2.56cm^3 be iron? Show work and explain.

Sagot :

First calculate density of the the metal (should equal to density of iron)

  • Mass=18.2g
  • Volume=2.56cm^3

[tex]\\ \bull\tt\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \bull\tt\longmapsto Density=\dfrac{18.2}{2.56}[/tex]

[tex]\\ \bull\tt\longmapsto Density=7.1g/cm^3[/tex]

Metal is not iron

Mass=18.2g

Volume=2.56cm^3

=> Density =

[tex] = > \frac{mass}{volume} [/tex]

=> Density=

[tex] \frac{18.2}{2.56} [/tex]

=> Density=

[tex]7.1g/cm {}^{3}

[/tex]

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