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Answered

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find the 35th term of the arithmetic sequence -5, 1, 7, 13, 19,...​

Sagot :

Answer:

1,7,13,19,.......

where a=1 & d=6(a2-a1=7-1=6)

an=a+(n-1)d

an=1+(n-1)6 [a=1,d=6]

an=1+6n-6

an=6n-5

6n-5 is the nth term of this sequence

Step-by-step explanation:

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The sequence is defined by the expression:

A(n)=6(n-1)-5

so, A(35) = 6(35-1) -5 = 204 - 5 = 199

The 35th term is 199.
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