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A person playing paintball fires a paintball horizontally at 59.1 m/s. The paintball travels a horizontal
distance of 70,9 meters. If the paintball is fired from the same height with an initial velocity that is 5 times
greater than the first shot, the paintball will travel a distance of meters?

A Person Playing Paintball Fires A Paintball Horizontally At 591 Ms The Paintball Travels A Horizontal Distance Of 709 Meters If The Paintball Is Fired From The class=

Sagot :

New initial velocity=59.1(5)=295.5m/s

We will use proportions to find the distance.

[tex]\\ \sf\longmapsto \dfrac{59.1}{70.9}=\dfrac{295.5}{x}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{70.9(295.5)}{59.1}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{20950.95}{59.1}[/tex]

[tex]\\ \sf\longmapsto x=354.5m[/tex]

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