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1)How fast is a ball moving when falling from rest and hits the ground 1.70
seconds later?

Sagot :

Lanuelidn

The final velocity of the ball is16.66 m/s.

Given the following data:

  • Initial velocity, U = 0 m/s (since the ball is falling from rest).
  • Time, t = 1.70 seconds.

We know that acceleration due to gravity (a) for a ball in free fall is equal to 9.8 meter per seconds square.

To find how fast (velocity) the ball is moving, we would use the first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

[tex]V = U + at[/tex]

Where:

  • V is the final velocity.
  • U is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]V = 0 + 9.8(1.7)[/tex]

[tex]V = 9.8[/tex] × [tex]1.70[/tex]

Final velocity, V = 16.66 m/s.

Therefore, the final velocity of the ball is16.66 m/s.

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