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A 8 kg brick is sitting on a frictionless table. If a 60 N horizontal force is applied to the brick and it accelerates at 2 m/s2, what will be the force of friction
a.24
b.44
c.0
d.600

Sagot :

b. 44

"F = ma"

let F be horizontal force applied and f be friction

F - f = ma
60 - f = 8 x 2
60 - f = 16
f = 60 - 16
f = 44N
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