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N.6 Properties of parallelograms

N6 Properties Of Parallelograms class=

Sagot :

Answer:

J=63

Step-by-step explanation:

3b+27=2b+57

subtract 27 from both sides

3b=2b+30

subtract 2b from both sides

b=30

K+J=180

substitute the value of b into K

2(30)+57+J=180

117+J=180

subtract 117 from both sides

J=63

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