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The population of a town grew from 20,000 to 28,000. The continuous growth rate is 15%. The equation mc024-1. Jpg represents the situation, where t is the number of years the population has been growing. About how many years has the population of the town been growing? Use a calculator and round your answer to the nearest whole number. 2 years 9 years 17 years 22 years.

Sagot :

Abidemiokinidn

The population of the town has been growing for about 2 years Given the equation that represents the situation expressed as:

[tex]20,000e^{0.15t}=28000[/tex]

where t is the time taken.

To get the value of t;

[tex]20,000e^{0.15t}=28000\\e^{0.15t} = \frac{28000}{20000} \\e^{0.15t} = 1.4[/tex]

Take the ln of both sides

[tex]ln e^{0.15t}=ln1.4\\0.15t=0.3365\\t = \frac{0.3365}{0.15}\\t= 2.24years[/tex]

This shows that the population of the town has been growing for about 2 years

Learn more on exponential functions here: https://brainly.com/question/19742435

Garylul69idn

Answer:

2 years

Step-by-step explanation:

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