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In 2009, John bought a new boat for $26,500. The boat was worth $20,500 in the year 2012. if John knows that the value of the boat depreciated linearly, what was the
annual rate of change of the boat's value? Round your answer to the nearest hundredth if necessary



Sagot :

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

[tex](\stackrel{x_1}{2009}~,~\stackrel{y_1}{26500})\qquad (\stackrel{x_2}{2012}~,~\stackrel{y_2}{20500}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{20500}-\stackrel{y1}{26500}}}{\underset{run} {\underset{x_2}{2012}-\underset{x_1}{2009}}}\implies \cfrac{-6000}{3}\implies -2000[/tex]