How many grams are in 3.4 moles of Lead (IV) Sulfate (Pb(SO4)2)? ) Molar mass: 303.26 g/mol 131.0840

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05-12-2021
Chemistry

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How many grams are in 3.4 moles of Lead (IV) Sulfate (Pb(SO4)2)? ) Molar mass: 303.26 g/mol 131.0840

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Shakilhussain2022idn Shakilhussain2022idn · Answer 1 · 2021-12-05T22:21:49-05:00

Shakilhussain2022idn Shakilhussain2022idn

05-12-2021

Answer:

1031.084g

Explanation:

n=m/M

m=n(M)

m = (3.4mol)(303.26g/mol)

1031.084g

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Ejkraljic21idn Ejkraljic21idn · Answer 2 · 2021-12-05T22:22:57-05:00

Ejkraljic21idn Ejkraljic21idn

05-12-2021

Answer:

1031.08

Explanation:

You start with 3.4 moles and you know that 6.022 x 10 ^ 23 = 1 mole( Avogadro's Number), so you just multiply those 2 numbers and the moles will cancel leaving you with grams of Lead Sulfate.

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