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Neeeeed help please, and thanks! :)))
[tex]\sf 4(2x-3)=6x+2[/tex]

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Answer:

[tex]\sf 4(2x-3)=6x+2 \\ \sf{8x - 12 = 6x + 2} \\ \sf{8x - 6x = 2 + 12} \\ \sf{2x = 14} \\ \sf{x = \frac{14}{2} = 7}[/tex]

The value of x from the given equation expression is; x = 7

Algebra Properties

We are given the equation;

4(2x - 3) = 6x + 2

The first step is to use distributive property to open the bracket to get;

(4 * 2x) - (4 * 3) = 6x + 2

8x - 12 = 6x + 2

Second step is to use subtraction property of equality to add 12 to both sides to get;

8x - 12 + 12 = 6x + 2 + 12

8x = 6x + 14

8x - 6x = 14

2x = 14

x = 14/2

x = 7

Read more algebra properties at; https://brainly.com/question/4344214

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