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The sum of two numbers is 40. The larger number is 8 more than the smaller number. What are the numbers?​

Sagot :

ItsYourDeepak254idn

Answer:

Hey There !

Let's solve....

Let the larger number be x

Let the smaller number be y

So

Now x+y=40

So just add 40+8=48

We know that

[tex]2x = 48 \\ \\ \therefore \: x = \frac{48}{2} \\ \\ simplify \\ \\ \frac{ \cancel{48} \: ^{24} }{ \cancel{2} } [/tex]

So larger number is 24

To find the smaller number.... Just subtract The total number by larger number that is

[tex]40 - 24 = 16 \\ \\ [/tex]

So 16 is the smaller number...

Larger number is 24 and smaller is 16

I hope it is helpful to you...

Cheers!_________________

0090086idn

Answer:

16 and 24

Step-by-step explanation:

we can do trial and improvement

let's start with 18 and 26

= 44

let's try something smaller

16 and 24

=40

the answer is 40

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