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Sagot :
The masses of the following amount of compound are as follows:
a. 2080.12 grams of barium iodide
b.1139.2 grams of sulphur dioxide
c. 96.25 grams of AspirinTM
d. 27.144 grams of magnesium nitrite
The molarity formula is represented as follows;
molarity = mass / molar mass
Recall we are ask to find the masses of the compounds. Therefore,
- mass = molarity × molar mass
Mass of BaI₂
a 5.32 mol barium iodide, BaI₂
molarity = 5.32 mol
molar mass of BaI₂ = 137 + 127(2) = 137 + 254 = 391 g/mol
mass = 5.32 × 391 = 2080.12 grams.
Mass of SO₂
b. ) 17.8 mol sulphur dioxide, SO₂
molarity = 17.8 mol
molar mass of SO₂ = 32 + 32 = 64 g /mol
mass = 17.8 × 64 = 1139.2 grams.
Mass of CHO₄
c. 1.25 mol AspirinTM, CHO₄
molarity = 1.25 mol
molar mass of CHO₄ = 12 + 1 + 64 = 77 g / mol
mass = 1.25 × 77 = 96.25 grams
Mass of Mg(NO₂)₂
d. 0.234 mol magnesium nitrite, Mg(NO₂)₂
molarity = 0.234 mol
molar mass = 24 + 14(2) + 32(2) = 24 + 28 + 64 = 116 g/mol
mass = 116 × 0.234 = 27.144 grams.
learn more on masses here: https://brainly.com/question/10312739?referrer=searchResults
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