IDNLearn.com provides a collaborative environment for finding and sharing knowledge. Ask your questions and receive comprehensive and trustworthy answers from our experienced community of professionals.

really need help with this problem

Really Need Help With This Problem class=

Sagot :

The equation of a circle is the equation that represents the circle on the coordinate plane

The equation of the circle is [tex](x +3)^2 + (y -6)^2 = 13[/tex]'

From the attached figure, we have the following parameters:

  • Center: (a,b) = (-3, 6)
  • Point on the circumference: (x,y) = (0,8)

Start by calculating the radius r using the following distance formula

[tex]d = \sqrt{(x -a)^2 +(y - b)^2}[/tex]

So, we have:

[tex]r = \sqrt{(0 --3)^2 +(8 - 6)^2}[/tex]

[tex]r = \sqrt{9 +4}[/tex]

[tex]r = \sqrt{13}[/tex]

Square both sides

[tex]r^2 = 13[/tex]

The equation of the circle is then calculated as:

[tex](x - a)^2 + (y -b)^2 = r^2[/tex]

Substitute values for a and b

[tex](x - -3)^2 + (y -6)^2 = r^2[/tex]

This gives

[tex](x +3)^2 + (y -6)^2 = r^2[/tex]

Substitute [tex]r^2 = 13[/tex]

[tex](x +3)^2 + (y -6)^2 = 13[/tex]

Hence, the equation of the circle is [tex](x +3)^2 + (y -6)^2 = 13[/tex]'

Read more about circle equations at:

https://brainly.com/question/1559324